C Program To Implement Dictionary Using Hashing Algorithms -

display(dict);

Before diving into hashing, consider alternative dictionary implementations:

Hashing maps large, variable-sized keys to small, fixed-size integers representing array indices. The Hash Function

Let's break down the specific components of our implementation: 1. The Hashing Algorithm: DJB2 c program to implement dictionary using hashing algorithms

We covered:

-------------------------------------------------------------*/ int dict_delete(Dict *d, const char *key) unsigned int idx = hash(key, d->size); Node *curr = d->table[idx]; Node *prev = NULL;

When a "collision" occurs (two keys hitting the same index), the program looks at the next available slot ( hashIndex++ ). This is called . 3. Time Complexity Best Case : O(1) for all operations. This is called

Common hash functions for strings in C:

// Display all entries printf("\nDictionary contents:\n"); for (int i = 0; i < dict->size; i++) Entry *curr = dict->buckets[i]; if (curr) printf("Bucket %d: ", i); while (curr) printf("(%s:%d) ", curr->key, curr->value); curr = curr->next;

void dict_rehash(Dictionary *dict, int new_size) Entry **old_buckets = dict->buckets; int old_size = dict->size; dict->buckets = calloc(new_size, sizeof(Entry*)); dict->size = new_size; dict->count = 0; Common hash functions for strings in C: //

The same key must always produce the same hash index.

new_node->key = (char*) malloc(strlen(key) + 1); if (!new_node->key) free(new_node); fprintf(stderr, "Memory allocation failed for key string\n"); exit(EXIT_FAILURE);

In this paper, we implemented a dictionary using hashing algorithms in C programming language. We discussed the design and implementation of the dictionary, including the hash function, insertion, search, and deletion operations. The C code provided demonstrates the implementation of the dictionary using hashing algorithms. This implementation provides efficient insertion, search, and deletion operations, making it suitable for a wide range of applications.

while (choice != 6);